题目链接：HDU3081

【题意】有n个女生和n个男生，给出互相不讨厌的关系，再给出f个女生是朋友的关系，问能有几次不相同的完全匹配，每个男生可以和不讨厌的所有女生的朋友匹配；

【分析】最先想到的肯定是暴力二分匹配+删边，即所有匹配完后的边全部删除，只要能完全匹配就继续，最后能匹配几次就是答案；

网上又看到可以用网络流来做，把源点到女生连的边权值为k，男生到汇点边权也是k，则只要最大流等于n*k则就能匹配k次，这样可以二分枚举k，比上面的要快很多；

【AC CODE】

【二分匹配+删边】93ms

#include <cstdio>
#include <cstring>
#include <cctype>
#include <cmath>
#include <map>
//#include <unordered_map>
#include <queue>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;
typedef long long LL;
#define rep(i,a,n) for(int i = a; i < n; i++)
#define repe(i,a,n) for(int i = a; i <= n; i++)
#define per(i,n,a) for(int i = n; i >= a; i--)
#define clc(a,b) memset(a,b,sizeof(a))
const int INF = 0x3f3f3f3f, MAXN = 400+10, MAXM = 10000*2*2*2+10;
struct Edge{
	int next,u,v;
}edge[MAXM];
int head[MAXN],tol,st,ed, cap[MAXM], tmp, buf[MAXM], f[MAXN];
int vis[MAXN][MAXN];
bool del[MAXM];

void add_edge(int u, int v, int c)
{
	Edge e = {head[u],u,v};
	edge[tol] = e;
	cap[tol] = c;
	head[u] = tol++;
	Edge e1 = {head[v],v,u};
	edge[tol] = e1;
	cap[tol] = 0;
	head[v] = tol++;
}
int d[MAXN];
bool bfs()
{
	clc(d,-1);
	queue<int> q;
	q.push(st);
	d[st] = 0;
	while(!q.empty())
	{
		int u = q.front();q.pop();
		for(int i = head[u]; ~i; i = edge[i].next)
		{
			if(del[i]) continue;
			int v = edge[i].v;
			if(-1 == d[v] && cap[i])
			{
				d[v] = d[u]+1;
				q.push(v);
				if(~d[ed]) return true;
			}
		}
	}
	return false;
}
int stack[MAXN],top,cur[MAXN];
int maxflow()
{
	int ans = 0;
	while(bfs())
	{
		memcpy(cur,head,sizeof(head));
		int u = st;
		top = 0;
		while(1)
		{
			if(u == ed)
			{
				int flow = INF,loc;
				rep(i,0,top)
				{
					if(flow > cap[stack[i]])
					{
						flow = cap[stack[i]];
						loc = i;
					}
				}
				rep(i,0,top)
				{
					cap[stack[i]] -= flow;
					cap[stack[i]^1] += flow;
				}
				ans += flow;
				top = loc;
				u = edge[stack[top]].u;
			}
			for(int i = cur[u]; ~i; cur[u] = i = edge[i].next)
				if(cap[i] && d[u]+1 == d[edge[i].v] && !del[i]) break;
			if(~cur[u])
			{
				stack[top++] = cur[u];
				u = edge[cur[u]].v;
			}
			else
			{
				if(!top) break;
				d[u] = -1;
				u = edge[stack[--top]].u;
			}
		}
	}
	return ans;
}
int find(int x){return f[x] == x?x:f[x] = find(f[x]);}
int main()
{
#ifdef SHY
	freopen("e:\\1.txt", "r", stdin);
#endif
	int t;
	scanf("%d%*c", &t);
	while(t--)
	{
		int n,m,fn;
		scanf("%d %d %d%*c", &n, &m, &fn);
		clc(head,-1);
		clc(vis,0);
		tol = 0;
		rep(i,0,m)
		{
			int a,b;
			scanf("%d %d%*c", &a, &b);
			vis[a][b] = true;
		}
		repe(i,1,n) f[i] = i;
		rep(i,0,fn)
		{
			int a,b;
			scanf("%d %d%*c", &a, &b);
			int x = find(a), y = find(b);
			if(x != y) f[x]= y;
		}
		int fd[MAXN][MAXN]={0};
		repe(i,1,n)
		{
			int x = find(i);
			repe(j,1,n)
			{
				int y = find(j);
				if(x == y && i != j)
				{
					repe(k,1,n)
					{
						if(vis[j][k])
							vis[i][k] = true;
					}
				}
			}
		}
		repe(i,1,n)
		{
			repe(j,1,n) fd[i][j] = fd[i][j] || vis[i][j];
		}
		st = 0, ed = n*2+1;
		repe(i,1,n)
		{
			repe(j,1,n)
			{
				if(fd[i][j])
					add_edge(i,j+n,1);
			}
		}
		repe(i,1,n) add_edge(st,i,1), add_edge(i+n,ed,1);
		memcpy(buf,cap,sizeof(int)*tol);
		int ans = 0;
		clc(del,0);
		while(maxflow() == n)
		{
			ans++;
			for(int i = 0; i < tol; i += 2)
			{
				if(!cap[i] && edge[i].u != st && edge[i].v != ed)
				{
					//printf("%d->%d\n", edge[i].u,edge[i].v);
					del[i] = true;
				}
			}
			memcpy(cap,buf,sizeof(int)*tol);
		}
		printf("%d\n", ans);
	}
	return 0;
}

【网络流+二分】46ms

#include <cstdio>
#include <cstring>
#include <cctype>
#include <cmath>
#include <map>
//#include <unordered_map>
#include <queue>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;
typedef long long LL;
#define rep(i,a,n) for(int i = a; i < n; i++)
#define repe(i,a,n) for(int i = a; i <= n; i++)
#define per(i,n,a) for(int i = n; i >= a; i--)
#define clc(a,b) memset(a,b,sizeof(a))
const int INF = 0x3f3f3f3f, MAXN = 400+10, MAXM = 10000*2*2*2+10;
struct Edge{
    int next,u,v;
}edge[MAXM];
int head[MAXN],tol,st,ed, cap[MAXM], tmp, buf[MAXM], f[MAXN];
int vis[MAXN][MAXN];

void add_edge(int u, int v, int c)
{
    Edge e = {head[u],u,v};
    edge[tol] = e;
    cap[tol] = c;
    head[u] = tol++;
    Edge e1 = {head[v],v,u};
    edge[tol] = e1;
    cap[tol] = 0;
    head[v] = tol++;
}
int d[MAXN];
bool bfs()
{
    clc(d,-1);
    queue<int> q;
    q.push(st);
    d[st] = 0;
    while(!q.empty())
    {
        int u = q.front();q.pop();
        for(int i = head[u]; ~i; i = edge[i].next)
        {
            int v = edge[i].v;
            if(-1 == d[v] && cap[i])
            {
                d[v] = d[u]+1;
                q.push(v);
                if(~d[ed]) return true;
            }
        }
    }
    return false;
}
int stack[MAXN],top,cur[MAXN];
int maxflow()
{
    int ans = 0;
    while(bfs())
    {
        memcpy(cur,head,sizeof(head));
        int u = st;
        top = 0;
        while(1)
        {
            if(u == ed)
            {
                int flow = INF,loc;
                rep(i,0,top)
                {
                    if(flow > cap[stack[i]])
                    {
                        flow = cap[stack[i]];
                        loc = i;
                    }
                }
                rep(i,0,top)
                {
                    cap[stack[i]] -= flow;
                    cap[stack[i]^1] += flow;
                }
                ans += flow;
                top = loc;
                u = edge[stack[top]].u;
            }
            for(int i = cur[u]; ~i; cur[u] = i = edge[i].next)
                if(cap[i] && d[u]+1 == d[edge[i].v]) break;
            if(~cur[u])
            {
                stack[top++] = cur[u];
                u = edge[cur[u]].v;
            }
            else
            {
                if(!top) break;
                d[u] = -1;
                u = edge[stack[--top]].u;
            }
        }
    }
    return ans;
}
int find(int x){return f[x] == x?x:f[x] = find(f[x]);}
int main()
{
#ifdef SHY
    freopen("e:\\1.txt", "r", stdin);
#endif
    int t;
    scanf("%d%*c", &t);
    while(t--)
    {
        int n,m,fn;
        scanf("%d %d %d%*c", &n, &m, &fn);
        clc(head,-1);
        clc(vis,0);
        tol = 0;
        rep(i,0,m)
        {
            int a,b;
            scanf("%d %d%*c", &a, &b);
            vis[a][b] = true;
        }
        repe(i,1,n) f[i] = i;
        rep(i,0,fn)
        {
            int a,b;
            scanf("%d %d%*c", &a, &b);
            int x = find(a), y = find(b);
            if(x != y) f[x]= y;
        }
        repe(i,1,n)
        {
            int x = find(i);
            repe(j,1,n)
            {
                int y = find(j);
                if(x == y && i != j)
                {
                    repe(k,1,n)
                    {
                        if(vis[j][k])
                            vis[i][k] = true;
                    }
                }
            }
        }
        /*repe(i,1,n)
        {
            repe(j,1,n) fd[i][j] = fd[i][j] || vis[i][j];
        }*/
        st = 0, ed = n*2+1;
        repe(i,1,n)
        {
            repe(j,1,n)
            {
                if(vis[i][j])
                    add_edge(i,j+n,1);
            }
        }
        tmp = tol;
        repe(i,1,n) add_edge(st,i,INF), add_edge(i+n,ed,INF);
        memcpy(buf,cap,sizeof(int)*tmp);
        int x = 0, y = n+1,ans;
        while(x <= y)
        {
            int mid = (x+y)>>1;
            memcpy(cap,buf,sizeof(int)*tmp);
            rep(i,tmp,tol) cap[i] = mid;
            if(maxflow() == n*mid)
                x = mid+1, ans = mid;
            else y = mid-1;
        }
        printf("%d\n", ans);
    }
    return 0;
}